Winamp & Shoutcast Forums Woo Hoo for Proofs!

 7th February 2005, 20:37 #1 dlinkwit27 has no CT(Forum King)     Join Date: Sep 2000 Posts: 13,236 Woo Hoo for Proofs! Let u1, u2,...,uk be vectors in Rn and c be a scalar. Prove that the span of {u1, u, ..., uk} is equal to the span of {u1+cu2, u2, ..., uk}. NO! I DONT WANNA! This sucks /edit I think I may have it I hope so at least. Last edited by dlinkwit27; 7th February 2005 at 21:00.
 7th February 2005, 21:06 #2 mark Forum King     Join Date: Jul 2002 Location: Norn Ir'nd, leek... Posts: 6,285 sounds worse than integrating to find the area between two curves, using long division to factorize the cubic (my homework)...
 7th February 2005, 21:07 #3 mysterious_w Forum King     Join Date: Dec 2003 Location: Good ol' Britain Posts: 2,750 When I clicked on the link to this topic I'm sure it said "Woohoo for poofs!"
 7th February 2005, 21:11 #4 dlinkwit27 has no CT(Forum King)     Join Date: Sep 2000 Posts: 13,236 nobby: that stuff is easy (now) mysterious: sarsacim. I think that this will do it, but I am not sure. I get to meet with a group on wed. to check it. Let v be the vector u1+cu2. Vector v can also be written as a linear combination of u1, u2, …, uk with coefficients d such that d1=1, d2=c, and d3=d4=…=dk=0 such that: v = d1u1+d2u2+d3u3+…dkuk = 1u1+cu2+0u3+…+0uk = u1+cu2 Thus, we can conclude that v belongs to Rn, thereby making the span of {u1, u2, …, uk} equal to the span of {u1+c*u2, u2, ..., uk} by Theorem 1.6 (c).
 7th February 2005, 21:14 #5 deeder7001 Jesus Freak(Forum King)     Join Date: Aug 2002 Location: Tempe, AZ Posts: 5,562 how old are you dlink? i'm 20 and i don't think i learned any of that stuff in high school. i'm good with math but i don't think that's what was taught in the classes i got. There is no sig.
 7th February 2005, 21:19 #6 dlinkwit27 has no CT(Forum King)     Join Date: Sep 2000 Posts: 13,236 I just turned 20. I'm in my 4th semester of colege/university and am in Elementary Lineral Algebra: A Matrix Approach. Just to make it more fun, my professor wrote the book for this subject. Literally. It's nice sometimes, but if you dont understand the lectur or the book, you cant relaly refrence the other for clairity.
 7th February 2005, 21:32 #7 mysterious_w Forum King     Join Date: Dec 2003 Location: Good ol' Britain Posts: 2,750 man, and I thought my maths was hard. Top set at school, and today we revised bearings.
7th February 2005, 21:37   #8
deeder7001
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Quote:
 Originally posted by dlinkwit27 I just turned 20. I'm in my 4th semester of colege/university and am in Elementary Lineral Algebra: A Matrix Approach.
no wonder it didn't look familiar. i only got algebra when i was doing the college thing.

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7th February 2005, 22:27   #9
mark
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Quote:
 Originally posted by mysterious_w man, and I thought my maths was hard. Top set at school, and today we revised bearings.
i would kill for bearings...

 7th February 2005, 22:51 #10 k_rock923 \m/(Forum King)     Join Date: Jul 2003 Location: /bin/bash Posts: 7,850 remember logic proofs? I miss those. I'm in AP Calc AB. Senior year of high school. Never underestimate the bandwidth of a station wagon full of tapes hurtling down the highway.
 7th February 2005, 23:56 #11 dlinkwit27 has no CT(Forum King)     Join Date: Sep 2000 Posts: 13,236 wtf are bearings?
 8th February 2005, 01:54 #12 Hollow Major Dude     Join Date: Oct 2001 Location: Baker Lab, Ithaca NY Posts: 1,128 The logic is right in your proof. Basically its because u1+cu2 is a linear combination of u1...uk hence you haven't really changed the set your working with. (ie. you can regenerate any vector from u1..uk from a linear combination of u1+cu2, u2...uk) The moon is made of cheese. Oh for some tasty moon cheese. www.redtetrahedron.org
 8th February 2005, 02:55 #13 d0rk I contribute nothing.(Forum King)     Join Date: Jan 2003 Location: Virgacalementoflagantionio Posts: 3,030 2 + 2 = 5 The extent of my math skills. I came for the hatred. I stayed for the ballbag.
8th February 2005, 03:40   #14
has no CT
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Quote:
 Originally posted by Hollow The logic is right in your proof. Basically its because u1+cu2 is a linear combination of u1...uk hence you haven't really changed the set your working with. (ie. you can regenerate any vector from u1..uk from a linear combination of u1+cu2, u2...uk)
awesome! thanks much for the conformation! What math are you in/do you teach?

 8th February 2005, 05:57 #15 petitechloe664y Senior Member     Join Date: Jan 2005 Posts: 269 ei dork! looks like we have the same math teacher
8th February 2005, 09:15   #16
Hollow
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Quote:
 Originally posted by dlinkwit27 awesome! thanks much for the conformation! What math are you in/do you teach?
I'm currently dealing with a massive case of senioritis during the rundown to graduation. I'll have a B.S. in chemistry with a math minor come June. In the fall I'll be starting grad school at Cornell or Syracuse most likely.

The moon is made of cheese.
Oh for some tasty moon cheese.
www.redtetrahedron.org

8th February 2005, 13:36   #17
has no CT
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 Originally posted by Hollow I'm currently dealing with a massive case of senioritis during the rundown to graduation. I'll have a B.S. in chemistry with a math minor come June. In the fall I'll be starting grad school at Cornell or Syracuse most likely.
nice. Well congrats and making it that far. It's weird. The past 4 semesters have just flown by, and yet, it feels as if the next 6 are going to take forever to get through.

 Winamp & Shoutcast Forums Woo Hoo for Proofs!